Function K-Means Clustering

US Nas 100OANDA

詳細

⋅ 2020年9月7日午前10時50分

Description:
A Function that returns cluster centers for given data (X,Y) vector points.

Inputs:
_X: Array containing x data points.¹
_Y: Array containing y data points.¹
_number_of_clusters: number of clusters.

Note:
¹: _X and _Y size must match.

Outputs:
_centers_x: Array containing x data points.
_centers_y: Array containing y data points.

Resources:
rosettacode.org/wiki/K-means++_clustering
en.wikipedia.org/wiki/K-means_clustering

リリースノート

⋅ 2023年3月30日午前9時1分

Update to V5 and fixed a a few errors in the code. -_-*

jon2snow

⋅ 2023年3月29日午後9時36分

It is sadly not working, Message bar 0 in remove.array function, Index -1 is out of bounds, array size is 1.

RicardoSantos

⋅ 2023年3月30日午前9時2分

@jon2snow, fixed, thanks for reporting :)

luminaryfi

⋅ 2020年9月12日午後3時36分

Excellent Work @RicardoSantos !

joaoseguradocomercial

⋅ 2023年1月18日午前9時43分

nao roda

kakola

⋅ 2021年3月3日午後8時37分

Instead of vectors, can k-means clustering be used on simple linear sets of data?

RicardoSantos

⋅ 2021年3月3日午後10時58分

@kakola, you can use the same set for X, Y arrays to do 1d means, but there would be better methods to achieve that..

RicardoSantos

⋅ 2021年3月4日午前8時48分

@kakola, follow up: take a look at the comments in this OS discussion:

kakola

⋅ 2021年3月4日午後2時41分

@RicardoSantos, I will try to find a clustering algorithm where N-clusters does not have to be initially provided.

RicardoSantos

⋅ 2021年3月4日午後2時47分

@kakola, sry missing link .p
stats.stackexchange.com/questions/40454/determine-different-clusters-of-1d-data-from-database

ruimnetob

⋅ 2020年9月19日午後10時11分

@RicardoSantos Olá Ricardo! Esta implementação de clustering por K-Means está funcional? Obrigado!

詳細